Optimal. Leaf size=204 \[ -\frac {5 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )}{9 a^{8/3} d e^3}+\frac {5 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} (c+d x)+b^{2/3} (c+d x)^2\right )}{18 a^{8/3} d e^3}+\frac {5 b^{2/3} \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} (c+d x)}{\sqrt {3} \sqrt [3]{a}}\right )}{3 \sqrt {3} a^{8/3} d e^3}-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )} \]
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Rubi [A] time = 0.15, antiderivative size = 204, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {372, 290, 325, 200, 31, 634, 617, 204, 628} \[ -\frac {5 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )}{9 a^{8/3} d e^3}+\frac {5 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} (c+d x)+b^{2/3} (c+d x)^2\right )}{18 a^{8/3} d e^3}+\frac {5 b^{2/3} \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} (c+d x)}{\sqrt {3} \sqrt [3]{a}}\right )}{3 \sqrt {3} a^{8/3} d e^3}-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )} \]
Antiderivative was successfully verified.
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Rule 31
Rule 200
Rule 204
Rule 290
Rule 325
Rule 372
Rule 617
Rule 628
Rule 634
Rubi steps
\begin {align*} \int \frac {1}{(c e+d e x)^3 \left (a+b (c+d x)^3\right )^2} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {1}{x^3 \left (a+b x^3\right )^2} \, dx,x,c+d x\right )}{d e^3}\\ &=\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}+\frac {5 \operatorname {Subst}\left (\int \frac {1}{x^3 \left (a+b x^3\right )} \, dx,x,c+d x\right )}{3 a d e^3}\\ &=-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}-\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{a+b x^3} \, dx,x,c+d x\right )}{3 a^2 d e^3}\\ &=-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}-\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx,x,c+d x\right )}{9 a^{8/3} d e^3}-\frac {(5 b) \operatorname {Subst}\left (\int \frac {2 \sqrt [3]{a}-\sqrt [3]{b} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,c+d x\right )}{9 a^{8/3} d e^3}\\ &=-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}-\frac {5 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )}{9 a^{8/3} d e^3}+\frac {\left (5 b^{2/3}\right ) \operatorname {Subst}\left (\int \frac {-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,c+d x\right )}{18 a^{8/3} d e^3}-\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,c+d x\right )}{6 a^{7/3} d e^3}\\ &=-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}-\frac {5 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )}{9 a^{8/3} d e^3}+\frac {5 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} (c+d x)+b^{2/3} (c+d x)^2\right )}{18 a^{8/3} d e^3}-\frac {\left (5 b^{2/3}\right ) \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} (c+d x)}{\sqrt [3]{a}}\right )}{3 a^{8/3} d e^3}\\ &=-\frac {5}{6 a^2 d e^3 (c+d x)^2}+\frac {1}{3 a d e^3 (c+d x)^2 \left (a+b (c+d x)^3\right )}+\frac {5 b^{2/3} \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} (c+d x)}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{3 \sqrt {3} a^{8/3} d e^3}-\frac {5 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )}{9 a^{8/3} d e^3}+\frac {5 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} (c+d x)+b^{2/3} (c+d x)^2\right )}{18 a^{8/3} d e^3}\\ \end {align*}
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Mathematica [A] time = 0.06, size = 169, normalized size = 0.83 \[ \frac {5 b^{2/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} (c+d x)+b^{2/3} (c+d x)^2\right )-\frac {6 a^{2/3} b (c+d x)}{a+b (c+d x)^3}-\frac {9 a^{2/3}}{(c+d x)^2}-10 b^{2/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} (c+d x)\right )-10 \sqrt {3} b^{2/3} \tan ^{-1}\left (\frac {2 \sqrt [3]{b} (c+d x)-\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{18 a^{8/3} d e^3} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.06, size = 527, normalized size = 2.58 \[ -\frac {15 \, b d^{3} x^{3} + 45 \, b c d^{2} x^{2} + 45 \, b c^{2} d x + 15 \, b c^{3} - 10 \, \sqrt {3} {\left (b d^{5} x^{5} + 5 \, b c d^{4} x^{4} + 10 \, b c^{2} d^{3} x^{3} + b c^{5} + {\left (10 \, b c^{3} + a\right )} d^{2} x^{2} + a c^{2} + {\left (5 \, b c^{4} + 2 \, a c\right )} d x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \arctan \left (\frac {2 \, \sqrt {3} {\left (a d x + a c\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {2}{3}} - \sqrt {3} b}{3 \, b}\right ) + 5 \, {\left (b d^{5} x^{5} + 5 \, b c d^{4} x^{4} + 10 \, b c^{2} d^{3} x^{3} + b c^{5} + {\left (10 \, b c^{3} + a\right )} d^{2} x^{2} + a c^{2} + {\left (5 \, b c^{4} + 2 \, a c\right )} d x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \log \left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2} + a^{2} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {2}{3}} + {\left (a b d x + a b c\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}}\right ) - 10 \, {\left (b d^{5} x^{5} + 5 \, b c d^{4} x^{4} + 10 \, b c^{2} d^{3} x^{3} + b c^{5} + {\left (10 \, b c^{3} + a\right )} d^{2} x^{2} + a c^{2} + {\left (5 \, b c^{4} + 2 \, a c\right )} d x\right )} \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}} \log \left (b d x + b c - a \left (-\frac {b^{2}}{a^{2}}\right )^{\frac {1}{3}}\right ) + 9 \, a}{18 \, {\left (a^{2} b d^{6} e^{3} x^{5} + 5 \, a^{2} b c d^{5} e^{3} x^{4} + 10 \, a^{2} b c^{2} d^{4} e^{3} x^{3} + {\left (10 \, a^{2} b c^{3} + a^{3}\right )} d^{3} e^{3} x^{2} + {\left (5 \, a^{2} b c^{4} + 2 \, a^{3} c\right )} d^{2} e^{3} x + {\left (a^{2} b c^{5} + a^{3} c^{2}\right )} d e^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 250, normalized size = 1.23 \[ \frac {5 \, {\left (2 \, \sqrt {3} \left (-\frac {b^{2}}{a^{2} d^{3}}\right )^{\frac {1}{3}} \arctan \left (-\frac {b d x + b c - \left (-a b^{2}\right )^{\frac {1}{3}}}{\sqrt {3} b d x + \sqrt {3} b c + \sqrt {3} \left (-a b^{2}\right )^{\frac {1}{3}}}\right ) - \left (-\frac {b^{2}}{a^{2} d^{3}}\right )^{\frac {1}{3}} \log \left (4 \, {\left (\sqrt {3} b d x + \sqrt {3} b c + \sqrt {3} \left (-a b^{2}\right )^{\frac {1}{3}}\right )}^{2} + 4 \, {\left (b d x + b c - \left (-a b^{2}\right )^{\frac {1}{3}}\right )}^{2}\right ) + 2 \, \left (-\frac {b^{2}}{a^{2} d^{3}}\right )^{\frac {1}{3}} \log \left ({\left | b d x + b c - \left (-a b^{2}\right )^{\frac {1}{3}} \right |}\right )\right )} e^{\left (-3\right )}}{18 \, a^{2}} - \frac {{\left (b d x + b c\right )} e^{\left (-3\right )}}{3 \, {\left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3} + a\right )} a^{2} d} - \frac {e^{\left (-3\right )}}{2 \, {\left (d x + c\right )}^{2} a^{2} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.02, size = 186, normalized size = 0.91 \[ -\frac {b x}{3 \left (b \,d^{3} x^{3}+3 b c \,d^{2} x^{2}+3 b \,c^{2} d x +b \,c^{3}+a \right ) a^{2} e^{3}}-\frac {b c}{3 \left (b \,d^{3} x^{3}+3 b c \,d^{2} x^{2}+3 b \,c^{2} d x +b \,c^{3}+a \right ) a^{2} d \,e^{3}}-\frac {5 \ln \left (-\RootOf \left (b \,d^{3} \textit {\_Z}^{3}+3 b \,d^{2} c \,\textit {\_Z}^{2}+3 b d \,c^{2} \textit {\_Z} +b \,c^{3}+a \right )+x \right )}{9 a^{2} d \,e^{3} \left (d^{2} \RootOf \left (b \,d^{3} \textit {\_Z}^{3}+3 b \,d^{2} c \,\textit {\_Z}^{2}+3 b d \,c^{2} \textit {\_Z} +b \,c^{3}+a \right )^{2}+2 c d \RootOf \left (b \,d^{3} \textit {\_Z}^{3}+3 b \,d^{2} c \,\textit {\_Z}^{2}+3 b d \,c^{2} \textit {\_Z} +b \,c^{3}+a \right )+c^{2}\right )}-\frac {1}{2 \left (d x +c \right )^{2} a^{2} d \,e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {5 \, b d^{3} x^{3} + 15 \, b c d^{2} x^{2} + 15 \, b c^{2} d x + 5 \, b c^{3} + 3 \, a}{6 \, {\left (a^{2} b d^{6} e^{3} x^{5} + 5 \, a^{2} b c d^{5} e^{3} x^{4} + 10 \, a^{2} b c^{2} d^{4} e^{3} x^{3} + {\left (10 \, a^{2} b c^{3} + a^{3}\right )} d^{3} e^{3} x^{2} + {\left (5 \, a^{2} b c^{4} + 2 \, a^{3} c\right )} d^{2} e^{3} x + {\left (a^{2} b c^{5} + a^{3} c^{2}\right )} d e^{3}\right )}} - \frac {\frac {5}{6} \, b {\left (\frac {2 \, \sqrt {3} \left (\frac {1}{a^{2} b}\right )^{\frac {1}{3}} \arctan \left (-\frac {b d x + b c + \left (a b^{2}\right )^{\frac {1}{3}}}{\sqrt {3} b d x + \sqrt {3} b c - \sqrt {3} \left (a b^{2}\right )^{\frac {1}{3}}}\right )}{d} - \frac {\left (\frac {1}{a^{2} b}\right )^{\frac {1}{3}} \log \left (4 \, {\left (\sqrt {3} b d x + \sqrt {3} b c - \sqrt {3} \left (a b^{2}\right )^{\frac {1}{3}}\right )}^{2} + 4 \, {\left (b d x + b c + \left (a b^{2}\right )^{\frac {1}{3}}\right )}^{2}\right )}{d} + \frac {2 \, \left (\frac {1}{a^{2} b}\right )^{\frac {1}{3}} \log \left ({\left | b d x + b c + \left (a b^{2}\right )^{\frac {1}{3}} \right |}\right )}{d}\right )}}{3 \, a^{2} e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.10, size = 291, normalized size = 1.43 \[ -\frac {\frac {5\,b\,c^3+3\,a}{6\,a^2\,d}+\frac {5\,b\,d^2\,x^3}{6\,a^2}+\frac {5\,b\,c^2\,x}{2\,a^2}+\frac {5\,b\,c\,d\,x^2}{2\,a^2}}{x\,\left (5\,b\,d\,c^4\,e^3+2\,a\,d\,c\,e^3\right )+x^2\,\left (10\,b\,c^3\,d^2\,e^3+a\,d^2\,e^3\right )+a\,c^2\,e^3+b\,c^5\,e^3+b\,d^5\,e^3\,x^5+5\,b\,c\,d^4\,e^3\,x^4+10\,b\,c^2\,d^3\,e^3\,x^3}-\frac {5\,b^{2/3}\,\ln \left (b^{1/3}\,c+a^{1/3}+b^{1/3}\,d\,x\right )}{9\,a^{8/3}\,d\,e^3}+\frac {5\,b^{2/3}\,\ln \left (2\,b^{1/3}\,c-a^{1/3}+2\,b^{1/3}\,d\,x-\sqrt {3}\,a^{1/3}\,1{}\mathrm {i}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{9\,a^{8/3}\,d\,e^3}-\frac {5\,b^{2/3}\,\ln \left (2\,b^{1/3}\,c-a^{1/3}+2\,b^{1/3}\,d\,x+\sqrt {3}\,a^{1/3}\,1{}\mathrm {i}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{9\,a^{8/3}\,d\,e^3} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.11, size = 233, normalized size = 1.14 \[ \frac {- 3 a - 5 b c^{3} - 15 b c^{2} d x - 15 b c d^{2} x^{2} - 5 b d^{3} x^{3}}{6 a^{3} c^{2} d e^{3} + 6 a^{2} b c^{5} d e^{3} + 60 a^{2} b c^{2} d^{4} e^{3} x^{3} + 30 a^{2} b c d^{5} e^{3} x^{4} + 6 a^{2} b d^{6} e^{3} x^{5} + x^{2} \left (6 a^{3} d^{3} e^{3} + 60 a^{2} b c^{3} d^{3} e^{3}\right ) + x \left (12 a^{3} c d^{2} e^{3} + 30 a^{2} b c^{4} d^{2} e^{3}\right )} + \frac {\operatorname {RootSum} {\left (729 t^{3} a^{8} + 125 b^{2}, \left (t \mapsto t \log {\left (x + \frac {- 9 t a^{3} + 5 b c}{5 b d} \right )} \right )\right )}}{d e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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